F(0)=4x^2+3x-3

Solution for F(0)=4x^2+3x-3 equation:

(0)=4F^2+3F-3

We move all terms to the left:

(0)-(4F^2+3F-3)=0

We add all the numbers together, and all the variables

-(4F^2+3F-3)=0

We get rid of parentheses

-4F^2-3F+3=0

a = -4; b = -3; c = +3;
Δ = b2-4ac
Δ = -32-4·(-4)·3
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{57}}{2*-4}=\frac{3-\sqrt{57}}{-8}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{57}}{2*-4}=\frac{3+\sqrt{57}}{-8}
$